Question

pls tell me what the answer of this​

Answer 1

Answer:

what is your question?

Answer 2

x=1/2 and y=1/3

Step-by-step explanation:

let 1/x=u and 1/y=v

we will get

u/2+v/3=2; u/3+v/2=13/6

take LCM

3u/6 + 2v/6 = 2; 2u/6 + 3v/6= 13/6

take 1/6 is common

1/6(3u+2v)=2; 1/6(2u+3v)=13/6

shift 1/6 to LHS

3u+2v=2÷1/6; 2u+3v= 13/6 ÷1/6

3u+2v=2×6; 2u+3v=13/6×6

3u+2v=12 -eq^n 1; 2u+3v=13 -eq^n 2

3u+2v=12

u=12-2v/3 -eq^n 3

put eq^n 3 in eq^n 2

2u+3v=13

2(12-2v/3)+3v=13

24-4v/3 + 3v= 13

take LCM

24-4v+9v/3=13

shift 1/3 to LHS

24-4v+9v=13×3

24+5v=39

5v=39-24

5v=15

v=15/5

v=3

put v=3 in eq^n 3

u=12-2v/3

u=12-2(3)/3

u=12-6/3

u=6/3

u=2

but x and y is

u=1/x ; v=1/y

2=1/x ; 3= 1/y

2x=1 ; 3y=1

x=1/2 ; y=1/3

therefore x=1/2 and y=1/3