pls tell no useless answers
Answers
Step-by-step explanation:
Area of trapazium will be
A = 26 cm.
Answer:
88 cm²
Step-by-step explanation:
The measures of parallel sides are 8 cm and (8+6) cm
we can calculate height by using Pythagoras theorem.
In ∆BCE,
the triangle is a right angled triangle.
hypotenuse = 10 cm
one side = 6 cm
let other side = a cm
By Pythagoras theorem,
The square of the hypotenuse is equal to the sum of the squares of the other two sides.
10² = 6² + a²
100 = 36 + a²
a² = 100 – 36
a² = 64
a = √64
a = 8 cm
So, height = 8 cm
Area of trapezium :
= ½(height) (sum of parallel sides)
= ½ (8 cm) (8+8+6)
= 4 cm × 22 cn
= 88 cm²
_________________________
(or)
In ∆BCE,
a = 8 cm
Hence, CE = 8 cm
In quadrilateral ADCE, all the sides are equal. Hence it is a square.
Area of square ADCE :
side of the square = 8 cm
Area = side²
Area = (8 cm)²
Area = 64 cm²
Area of ∆BCE,
base = 6 cm
height = 8 cm
Area of right angled triangle = ½ × base × height
Area = ½ × 6 cm × 8 cm
Area = 24 cm²
Area of the trapezium,
= Area of square ADCE + area of ∆BCE
= 64 cm² + 24 cm²
= 88 cm²