Question

Pls tell ques 7 and 8

Answer 1

Answer:

Explanation:pH=log1(H+)=−log(H+)pOH=log1(OH−)=−log(OH−)

But we have said that (H+)(OH−) = Kw

Therefore (pH)(pOH)= −log Kw

Now if (H+)=10−7

pH = log 10−7 = pH 7.0

or (H+) = 10−2

pH = log 10−2 = pH 2.0