Question

Pls tell Question number 8 figure is also there​

Answer 1

Step-by-step explanation:

In triangle BCD:

angle CDB+angleDCB+ angle CBD=180

LET angle CDB=1 DCB=2 CBD=3

angle1+angle +angle3=180

2x+5x+3x=180

10x=180

x=18

2x=2×18=36

3x=3×18=54

5x=5×18=90

angle 2 is equal to angle A=90 ( because opposite angles of parallelogram are equal)

angle ADB=90-36=54

angle ABD=90-54=36;

angle B=36+54=90

angle D=54+36=90

hence;

angle A ,angle b, angle C,angle D are 90 degree all

Answer 2

Step-by-step explanation:

☺❤In triangle BCD:

angle CDB+angleDCB+ angle CBD=180

LET angle CDB=1 DCB=2 CBD=3

angle1+angle +angle3=180

2x+5x+3x=180

10x=180

x=18

2x=2×18=36

3x=3×18=54

5x=5×18=90

angle 2 is equal to angle A=90 ( because opposite angles of parallelogram are equal)

angle ADB=90-36=54

angle ABD=90-54=36;

angle B=36+54=90

angle D=54+36=90

hence;

angle A ,angle b, angle C,angle D are 90 degree all❤☺