Question

Pls tell step by step

Answer 1

Step-by-step explanation:

The attachment will surely help you

Answer 2

Answer:

₹ 6160

Step-by-step explanation:

Given:-

Inner diameter of the hemispherical bowl made of brass $(d)=14cm$

Inner radius of the hemispherical bowl made of brass $(r)=\frac{d}{2}$

⇒ $\frac{14}{2}$

$r=7 cm$

Rate of tin plating per $cm^2$ = ₹ 20

To find:-

Cost of tin plating the hemispherical bowl made of brass.

Solution:-

Curved Surface Area of the hemispherical bowl $=2\pi r^2$

⇒ $2$ × $\frac{22}{7}$ × $7$ ×

⇒ $2$ × $22$ × 7

⇒  $44$ × 7

⇒ $308cm^2$

∴ The curved surface area of the hemispherical bowl $= 308cm^2$

Rate of tin plating per $cm^2$ = ₹ 20 (∵ Given)

Cost of tin plating the hemispherical bowl made of brass per= Rate of tin plating per $cm^2$ × Curved Surface Area of the hemisphere

Cost of tin plating the hemispherical bowl made of brass =  20 × 308

⇒ ₹ 6160

∴ The cost of tin plating the hemispherical bowl made of brass =  ₹ 6160