Question

Pls tell teh answer

Answer 1

Answer:

given :

AP = BQ

PR = QS

From figure:

angle APS = angle BQR = 90°

In triangles APS and BQR:

AP = BQ -------------------S

angle APS = angleBQR----------A

PR = QS--------------------S

HENCE , ∆ APS is congruent to ∆ BQR.

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Answer 2

Step-by-step explanation:

IN Figure..

we take,

RS = X

SO WE GET,

PS = PR + X

AND

QR = QS + X

SO,

PS = QR.

>> NOW IN ∆APS & ∆BQR,

WE HAVE:-

• AP = BQ (GIVEN IN QUESTION)
• ANGLE APS = ANGLE BQS (90°)
• PS = QR (ALSO GIVEN IN QUESTION)

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