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Anonymous:
Hey buddy use the midpoint theorem
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by cpct DE=BC and DE=1\2BC
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in ∆ade and∆abc
ad/ab=ae/ac
since the ratios of the corresponding sider is equal, hence it is a similar triangle
now , acc. to bpt if the ratio of the corresponding sides is equal then the line drawn from the two sides is parallel to the third side. therefore, bc||de
and if bc||de then
acc. to mpt de=1/2bc
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