Question

pls tell the answer chapter 3 exponents and radicals worksheet 2 ​

Answer 1

Step-by-step explanation:

$lhs = { ({(729)}^{ \frac{ - 5}{3} } )}^{ \frac{ - 1}{2} } = {729}^{ \frac{ - 5}{3} \times - \frac{ - 1}{2} } \\ \\ = {729}^{ - \frac{5}{6} } \\ \\ = {3}^{ - 6 \times - \frac{5}{6} } \\ \\ = {3}^{ 5} \\ \\ \\ \\ rhs = {({(729)}^{ - \frac{5}{3} })}^{ \frac{ - 1}{2} } \\ \\ = {729}^{ \frac{5}{6} } \\ \\ = {3}^{6 \times \frac{5}{6} } \\ \\ = {3}^{5} \\ \\ = lhs$

$therefore \: \: \: lhs = rhs \\ \\ \\ hence \: proved.$