Question

pls tell the answer fast ​

Answer 1

Given :

• $\sf\:\frac{x+4}{2x+4}=\frac{1}{4}$

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To find :

• The value of x.

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Solution :

$\sf\:\frac{x+4}{2x+4}=\frac{1}{4}$

Cross multiplying

$\sf\implies\:4(x+4)=1(2x+4)$

$\sf\implies\:4x+16=2x+4$

Transposing 2x in LHS it becomes -2x

$\sf\implies\:4x-2x+16=4$

$\sf\implies\:2x+16=4$

Transposing +16 in RHS it becomes -16

$\sf\implies\:2x=4-16$

$\sf\implies\:2x=-12$

Transposing 2 to RHS it goes to the denominator

$\sf\implies\:x=\frac{-12}{2}$

Reducing the fraction to lower terms

$\sf\implies\:x=\cancel{\frac{-12}{2}}$

$\small{\underline{\boxed{\mathrm{\implies\:x=(-6)}}}}$ $\tt\color{teal}{\checkmark}$

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Verification :

Plugging the value of x as (-6)

$\sf\:\frac{x+4}{2x+4}=\frac{1}{4}$

$\sf\dashrightarrow\:\frac{(-6)+4}{2(-6)+4}=\frac{1}{4}$

$\sf\dashrightarrow\:\frac{-6+4}{-12+4}=\frac{1}{4}$

$\sf\dashrightarrow\:\frac{-2}{-8}=\frac{1}{4}$

Cross multiplying

$\sf\dashrightarrow\:(-2) \times 4=1 \times (-8)$

$\sf\dashrightarrow\:(-8)=(-8)$

$\bf\dashrightarrow\:LHS=RHS$

Hence Verified !~

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Henceforth‎ -

❒ The value of x is $\large{\mathfrak\purple{(-6)}}$

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Answer 2

$\LARGE\sf\underline{\red{Question}}:$

$\:\:\:\star \sf {Find \: Solution} : \dfrac{x+4}{2x+4} = \dfrac{1}{4}$
$\\\LARGE\sf\underline{\red{Solution}}:$

$\longmapsto\sf \dfrac{x+4}{2x+4} = \dfrac{1}{4} \\\\\bigstar\textbf{Cross Multiplying}\\\\\implies\sf 4(x+4)=1(2x+4) \\\\\bigstar\textbf{Opening brackets by multiplying}\\\\\implies \sf 4x+16=2x+4 \\\\\bigstar\textbf{Adding (-4x) on both the sides}\\\\\implies\sf 4x\blue{-4x}+16=2x+4\blue{-4x}\\\\\implies\sf \cancel{4x} \: \cancel{-4x} + 16 = -2x +4 \\\\\implies \sf 16 = -2x + 4\\\\\bigstar\textbf{Adding (-4) on both the sides } \\\\\implies 16\blue{-4} = -2x + 4 \blue{-4} \\\\\implies 12 = -2x + \cancel{4}\: \cancel{-4} \\\\\implies \sf 12=-2x \\\\\bigstar\textbf{dividing both sides by 2} \\\\\implies\sf \frac{12}{2} = \frac{-\cancel{2}x}{\cancel{2}} \\\\\implies 6 = -x \\\\\implies\underline{\boxed{\pink{x=-6}}}$

$\large\sf\underline{Therefore},$
• value of x is -6