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Explanation:
1. 5x-60+2x+40+3x-80=180°
2. 10x=280°
3. x=28°
4. Angle A=80, B=96 nd angle C=4
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angle (A) = 80° ,, angle (B) = 96° and angle (C) =4°
Explanation:
Using angle sum property of a ∆ we get
A+B+C= 180°
(5x-60°) + (2x+40°) + (3x-80°) =180°
by solving we have
10x-100°=180°
10x=280°
[x=28]
Now
A=5x28-60°= 80°
B=2x28+40°= 96°
C=3x28-80°= 4°
this is ur answer !!! hope it helps
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