Math, asked by kksnraju3, 1 month ago

pls tell the answer for this pls

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Answered by sangitabhowmik29
0

Answer:

1p(x)=5-4x+2x²

(I)putting the value p(0)

p(x)=5-4x0+2x(0)²

or,p(x)=5-0+2x0

or,p(x)=5-0+0

or,p(x)=5

(ii) putting the value p(3)

p(x)=5-4x3+2x(3)²

or,p(x)=5-4x3+2x9

or,p(x)=5-12+18

or,p(x)=11

(iii) putting the value p(-2)

p(x)=5-4x(-2)+2x(-2)²

p(x)=5+8+2x4

p(x)=11

Answered by dipikachoudhury266
3

I) First put x=0

Therefore,

p(0)=5-4*0+2*0²

= 5-0+0

= 5

II) Put x=3

Therefore,

p(3) = 5-4*3+2*3²

= 5-12+18

= 23-12

= 11

III) Put x=-2

Therefore,

p(-2) = 5-4*(-2)+2*(-2)²

= 5-8+8

= 5

Please mark it the brainliest answer

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