Pls tell the answer I will mark brainliedt
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Answer:
2–√(cos(3π4)+isin(3π4))
Step-by-step explanation:
1+7i(2−i)2=1+7i4−1−4i=1+7i3−4i
=1+7i3−4i∗3+4i3+4i=3+4i+21i−289+16
=−25+25i25=−1+i
So, r(cosθ+isinθ)=−1+i
∴rcosθ=−1andrsinθ=1
∴r2=2⇒r=2–√
cosθ=−12–√andsinθ=12–√
∴θ=3π4
So, polar form will be,
2–√(cos(3π4)+isin(3π4))
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