pls tell the answer of fifth question...
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m=2
As hcf will be 13
therefore 61(2)-117=13
As hcf will be 13
therefore 61(2)-117=13
Answered by
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the H.C.F of 65 and 117 is 13 ............found by method
According to the given condition
H.C.F of 65 and 117= 65m-117
13=65m-117
13+117=65m
130=65m
130/65=m
2=m
m=2
According to the given condition
H.C.F of 65 and 117= 65m-117
13=65m-117
13+117=65m
130=65m
130/65=m
2=m
m=2
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