Question

Pls tell the answer of this question

Answer 1

Answer:- Option (a) 7.5Ω

Step by step explanation:-

Question:-

⟶ What is the resistance of circuit?

Solution:-

The very step of solving this is naming all the resistors with R₁, R₂, . . . . . . so on. Naming all the resistors makes it easy to solve.

Now,

From the diagram we have:-

• R₁ = 10Ω
• R₂ = 10Ω
• R₃ = 10Ω
• R₄ = 10Ω

From the diagram, we can clearly see:-

• Resistors R₂, R₃ and R₄ are in series

We know,

Resistance in series combination is calculated as follows:-

• Rₛ = R₁ + R₂ + R₃ . . . . . . Rₙ

Hence,

Resistance in resistors R₂, R₃ and R₄ is as follows:-

Rₛ = 10 + 10 + 10

Rₛ = 30Ω

Now,

• We can see that Resistors Rₛ and R₁ are parallel

We know,

Resistance in parallel combination is calculated as follows:-

• $\sf{\dfrac{1}{R_p} = \dfrac{1}{R_1} + \dfrac{1}{R_2} + \dfrac{1}{R_3} . . . . . . . \dfrac{1}{R_n}}$

Hence,

Resistance in resistors Rₛ and R₁ are as follows:-

$\sf{\dfrac{1}{R_p} = \dfrac{1}{30} + \dfrac{1}{10}}$

= $\sf{\dfrac{1}{R_p} = \dfrac{1 + 3}{30}}$

= $\sf{\dfrac{1}{R_p} = \dfrac{4}{30}}$

= $\sf{R_p = \dfrac{30}{4}}$

= $\sf{R_p = 7.5\Omega}$

∴ The resistance across the circuit is of 7.5Ω

Hence Option (a) 7.5Ω is the correct answer.

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