Math, asked by dakshita74, 6 months ago

Pls tell the answer of this question...Pls​

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Answers

Answered by geetkrishan06
2

Answer:

50

Step-by-step explanation:

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Answered by Anonymous
11

Given:

 \sf3y -  \dfrac{1}{3y}  = 7

To find:

 \sf9{y}^{2}  + \dfrac{1}{9 {y}^{2} }

 \:

Solution:

We have,

 \sf3y -  \dfrac{1}{3y}  = 7

\bigstar {\mathfrak {\pink {On\ squaring\ both\ the\ sides.}}}

 \sf(3y -  \dfrac{1}{3y})^{2}   = (7)^{2}

\bigstar {\mathfrak {\red {Using\ identity\ (a-b)^{2} = a^{2} -2ab + b^{2}}}}

 \sf(3y)^{2} - 2 \times 3y \times  \dfrac{1}{3y}  +  { (\dfrac{1}{3y} })^{2}  = (7)^{2}

\sf9y^{2} - 2 \times \cancel{3y} \times  \dfrac{1}{\cancel{3y}}  +  { \dfrac{1}{9y^{2} } } = 49

\sf9y^{2} - 2 +  { \dfrac{1}{9y^{2} } } = 49

\sf9y^{2} +  { \dfrac{1}{9y^{2} } } = 49 + 2

{\boxed {\bf {\purple{9y^{2} +  { \dfrac{1}{9y^{2} } } = 51}}}}

 \:

Answer:

∴ Value of  \sf9{y}^{2}  + \dfrac{1}{9 {y}^{2} } is {\underline {\mathcal {\green {51}}}}

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