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Answer:
50g of CaCO3=1.
5∗(6. 022∗1023)=9.
035∗1023 oxygen atoms
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Answer:
The molecular formula of CaCO3 is 40+12+(16)3 = 100
50/100= 0.5mol of CaCO3.
From the formula, we can see that in 1 mol of CaCO3, 3 mol of oxygen atoms are present.
Hence, in 0.5 mol, we have 1.5 mol of oxygen atoms.
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