Question

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Answer 1

$\underline{\rm Question -}$

Two masses of 200 kg and 500 kg are kept at the distance of 2m. Find the gravitation force between them.

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$\underline{\rm Answer - }$

$\underline{\rm Given - }$

• $\rm m_1 = 200 kg$
• $\rm m_2 = 500 kg$
• $\rm r = 2m$

where

$\longrightarrow$$\rm m_1$ and $\rm$m_2 are the masses of object.

$\longrightarrow$r is the distance between them.

$\underline{\rm To\: find -}$

Gravitational force $\implies$ F

$\underline{\rm Formula \:used - }$

$\boxed{\rm\red{ F = \dfrac{Gm_1m_2}{r^2}}}$

• G is universal gravitation constant.
• $\rm m_1$ and $\rm$m_2 are the masses of object.
• r is the distance between them.

$\underline{\rm Solution - }$

$\implies$$\rm G = 6.67 \times 10^{-11} m^3 / kg s^2$

$\implies$$\rm m_1 = 200 kg$

$\implies$$\rm m_2 = 500 kg$

$\implies$$\rm r = 2m$

Substituting the value in formula -

$\rm F = \dfrac{Gm_1m_2}{r^2}$

$\implies$$\rm F = \dfrac{6.77 \times 10^{-11} \times 200 \times 500}{2^2}$

$\implies$$\rm F = \dfrac{677000 \times 10^{-11}}{4}$

$\implies$$\rm F = \dfrac{ 677 \times 10^{-8}}{4}$

$\implies$$\rm F = 169.25 \times 10^{-8} N$

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