Question

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Answer 1

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Answer 2

Answer...

$a = 1 \\ \sf \: b = - 2 \\ \\ \sf(1) \: {a}^{2} + {b}^{2} + 3ab \\ \sf = {(1)}^{2} + {( - 2)}^{2} + 3(1)( - 2) \\ \sf = 1 + 4 - 6 \\ \sf = 5 - 6 \\ \sf = - 1 \\ \\ \sf(2) \: {a}^{3} + {a}^{2}b + a {b}^{2} + {b}^{3} \\ \sf = {(1)}^{3} + {(1)}^{2} ( - 2) + {( - 2)}^{3} \\ \sf = 1 - 2 - 8 \\ \sf = 1 - 10 \\ \sf = - 9$