Question

pls tell the asnwer of this question

Answer 1

Step-by-step explanation:

if 3root3 ,2root2 sin²theta,sin theta are in GP then

$\frac{sinθ}{2 \sqrt{2} sin²θ} = \frac{2 \sqrt{2} sin²θ}{3 \sqrt{3} }$

because for a G.P ratio of two corresponding terms always remain same

$\frac{1}{2\sqrt{2}sinθ}=\frac{2 \sqrt{2} sin²θ}{3 \sqrt{3} }$

$3\sqrt{3}=8sin³θ$

$\frac{3\sqrt{3}}{8}=sin³θ$

$sinθ=\frac{\sqrt{3}}{2}$

$θ=60°$