Question

pls tell this question ​

Answer 1

Step-by-step explanation:

AB= BC

BC= CD

CD=DE

NOW,

AD= AB+BC+CD(Since AB+BC= AC AND AC+CD= AD)

AD= AB+AB+AB (SINCE, AB= BC= CD)

AD= 3AB

SIMILARLY,

BE= BC+CD+DE(SINCE BC+CD= BD AND BD + DE= BE)

BE= BC+BC+BC(SINCE BC= CD= DE)

BE= 3BC

SINCE

AB= BC

THEREFORE,

3AB= 3BC

SO,

SINCE 3AB=3BC

THEREFORE, AD= BE

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Answer 2

Answer:

Step-by-step explanation:AB= BC

BC= CD

CD=DA

NOW,

AD= AB+BC+CD(Since AB+BC= AC AND AC+CD= AD)

AD= AB+AB+AB (SINCE, AB= BC= CD)

AD= 3AB

SIMILARLY,BE= BC+CD+DE(SINCE BC+CD= BD AND BD + DE= BE)

BE= BC+BC+BC(SINCE BC= CD= DE)

BE= 3BC

SINCE

AB= BC

THEREFORE,

3AB= 3BC

SO,

SINCE 3AB=3BC

THEREFORE, AD= Bc