Question

pls tell this question fast​

Answer 1

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In △ABD,

∠BAD+∠ADB+∠B=180°

∠BAD+90° +∠B=180°

∠BAD=90° −∠B ......(1)

In △ABC,

∠A+∠B+∠C=180 °

∠B+∠C=90°

∠C=90° −∠B

∠ACB=90° −∠B .......(2)

From 1 and 2, we get,

∠BAD=∠ACB

Hence proved.

Answer 2

Step-by-step explanation:

GIVEN THAT:-

ABC IS A RIGHT ANGLE TRIANGLE

AD PERPENDICULAR TO BC

PROVE THAT:-

Angle BAD= Angle ACB

Triangal BAD = Triangle ACD (both are right angle) - - - (1)

Therefore

Angle DAC = Angle ABD

Angle CDA = Angle ADB

Therefore angle BAD = Angle ACB

PROVE!