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i)6.023×10 power of 23
ii)22.4L at S.T.P
iii)CaO+65.6=Ca(NO3)taken two times
and solve that way I explain
iv)5×weight of element /molecular weight of total compuned
C)
i)CH4NaCO3
ii)2CaCHO
iii)C2H6KBrO
please add brainlist to my answer
ii)22.4L at S.T.P
iii)CaO+65.6=Ca(NO3)taken two times
and solve that way I explain
iv)5×weight of element /molecular weight of total compuned
C)
i)CH4NaCO3
ii)2CaCHO
iii)C2H6KBrO
please add brainlist to my answer
agarwalmuskan442:
it's wrong
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