Question

Pls tell this question's answer pls​

Answer 1

Answer:

1

Step-by-step explanation:

According to the question, a = 111, d = -5

To find the nth term of an AP, we use the equation T = a + (n-1)d

Now, the T we need here has to be the last positive term of the progression, so we will say that T > 0

So, a + (n-1)d > 0

Putting values in this equation, we get:

111 + (n-1)×(-5) > 0

111 > 5n-5

116 > 5n

n < 116/5

n < 23.2

So the largest value of n that is an integer and satisfies this inequality is 23

Now we can calculate the value of T as 111 + 22×(-5) = 111 - 110 = 1

So the last positive term of the series will be 1