Question

pls thank you and also pls give step by step explanation

Answer 1

Answer:

130

Step-by-step explanation

in triangle acb, angle acb = 90(angle in a semicircle)

angle bac+abc+acb=180(angle sum property)

40+90+abc=180

130+abc=180

abc=180-130

abc=50

in quadrilateral abcd,

angle abc + angle adc=180(cyclic quadrilateral)

50+adc=180

adc=180-50

adc=130

hope it helps

Answer 2

Answer:

angle ACB = 90°(angle in a semicircle is 90°)

So, in ∆ABC,

180°-(40°+90°)=angle ABC

angle ABC=50°

Now,angle ABC +. angle ADC=180°(sum of opposite angles of a cyclic quadrilateral is 180°)

So, angle ADC =180°-50°

=130°