Question

pls this question. ​

Answer 1

Ans:-

In part (3)

Const.:- Join QP

In triangle QPM

Angle M = 90 degree [tangent is perpendicular to the radius of the circle]

Angle MPQ = 20 degree [ As PQ is the bisector]

So, in triangle PQM

Angle QPM+ Angle PMQ+ Angle MQP =180 degree

20 degree + 90 degree+ Angle MQP = 180 degree

110 degree + Angle MQP = 180 degree

Angle MQP = 180-110. Degree

Angle MQP = 70 degree

Similarly, Angle PQN = 70 degree

So, Angle MQN =70 degree + 70 degree

Angle MQN = 140 degree

Answer 2

1st answer is in the 1st attachment and 2nd and 3rd answer is in the 2nd attachment...

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