Question

pls this question. ​

Answer 1

This can help you

But the names in figure are changed

Answer 2

<E=<E ------- Common angles

<ETA = <EBT ------ Tangent secant theorem

∆EAT ~ ∆ETB ------ AA test of similarity.....

So,

ET/EB = EA/ET

Therefore,

EA × EB = ET^2

It's TANGENT SECANT SEGMENTS THEOREM

For more, you can refer the attachment

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