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Let the length of the rectangle be x cm and breadth be y cm
According to the first condition,
Perimeter = 2 (l+b)
40 = 2(x+y)
40 = 2x + 2y
20 = x + y............... (i)
According to the second condition,
x = 2y + 2
(because the length is 2 more than double the breadth)
Therefore,
x = 2y +2
x - 2y =2.............. (ii)
Solving the the equations (i) and (ii),
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____________________
0x - 3y = - 18
y = - 18/-3
y = 6
Substituting this in eqn (i),
x + y = 20
x + 6 = 20
x = 20 - 6
x = 14
Therefore length = 14cm and breadth = 6 cm
Hope this helps
Please mark my answer as BRAINLIEST
According to the first condition,
Perimeter = 2 (l+b)
40 = 2(x+y)
40 = 2x + 2y
20 = x + y............... (i)
According to the second condition,
x = 2y + 2
(because the length is 2 more than double the breadth)
Therefore,
x = 2y +2
x - 2y =2.............. (ii)
Solving the the equations (i) and (ii),
____________________
0x - 3y = - 18
y = - 18/-3
y = 6
Substituting this in eqn (i),
x + y = 20
x + 6 = 20
x = 20 - 6
x = 14
Therefore length = 14cm and breadth = 6 cm
Hope this helps
Please mark my answer as BRAINLIEST
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