pls urgent..............
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5 tan θ= 4
tan θ= 4/5
Let perpendicular=4k base= 5k
Hypotenuse= √16k²+25k²= √41 k
sin θ= 5/√41 cos θ=4/√41
5sinθ-3cosθ / 5sinθ+cosθ
= 25/√41-12/√41 / 25/√41+4/√41
= 13/29
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