PLS VERY URGANT
in a parallelogram abcd e and f are the midpoints of sides ab and c such that ae=cf prove that ed parallel to bf
spriya:
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given: ABCD is a parallelogram and AE = CF.......(1).
TPT: EDBF
proof:
since the opposite sides of the parallelogram are equal.
AB = CD.......(2)
subtract (1) from (2):
.......(3)
and BE is parallel to DF, therefore BEDF is a parallelogram.
thus ED is parallel to BF.
hope this helps you.
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E is the midpoint of AB. F is the midpoint of CD
AE = CF (given)
AE=BE (E is the mid point of AB)
similarly, CF=DF (F is the mid point)
AE +BE= CF+DF
AB=CD
AB11 CD ( opp.sides of parallelogram are equal and parallel)
AE = CF (given)
AE=BE (E is the mid point of AB)
similarly, CF=DF (F is the mid point)
AE +BE= CF+DF
AB=CD
AB11 CD ( opp.sides of parallelogram are equal and parallel)
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