Math, asked by saralapari2008, 5 months ago

Pls with explanation. Fast ​

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Answered by RitikaKandari
0

Answer:

= (x²+2x-15) / (2x²+13x+15)

= (x²+5x-3x-15) / (2x²+ 10x+3x +15)

= [x(x+5) -3(x+5)] / [2x(x+5) +3(x+5)]

= [(x+5)(x-3)] / [(x+5)(2x+3)]

= x-3/2x+3

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