pls write all the steps on paper and attach it
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Verified by peehu
D
1.2 x 10 ºg
Correct option is
Let the solubility of AgBr be S mol litre
AgBr Ag+Br¯
Hence, [Ag][Br] = 5 x 10-13
[Ag+] = 0.05
So [Br] 10-¹¹M.
It means 10-11 moles of KBr moles in 1 litre of solution.
molecular mass of KBr = 120 gmol -1
So 1.2 x 10 g of KBr to be added to 1 litre of 0.05M solution of silver nitrate to start precipitation of AgBr.
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