Question

pls write in your copy and send the pic I need it's answer I will mark it brainliieast pls answer as soon as possible​

Answer 1

Answer:

Answer:-

V = 10m/s

S = 25 m

Given:-

u = 0

a = 2m/s²

T = 5s

To find :-

Velocity acquired and distance travelled.

Solution :-

Since, acceleration is constant so we can use the equation of motion.

\boxed{\sf{v = u + at}}

v=u+at

put the given value,

v = atv=at

v = 2 \times 5v=2×5

v = 10m/sv=10m/s

Now, distance travelled :-

\boxed{\sf{S = ut + \dfrac {1}{2}at^2}}

S=ut+

2

1

at

2

S = \dfrac {1}{2}at^2S=

2

1

at

2

S = \dfrac {1}{2}\times 2 .(5)^2S=

2

1

×2.(5)

2

S = \dfrac {1}{2}\times 50S=

2

1

×50

S = 25 mS=25m

hence, V = 10 m/s

hence, V = 10 m/sS = 25 m.