Question

plsanswer 1 and 2 both

Answer 1

here's both the answer!

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Answer 2

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in the 1st figure :

AB is a straight line ......

oc stands on it .....

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$\angle \: aoc \: + \: \angle \: boc \: = 180\degree \\ \\ (2x - 10)\degree + \: (3x + 20)\degree = 180\degree \\ \\ 2x + 3x - 10 + 20 = 180\degree$

$(5x + 10)\degree = 180 \\ \\ 5x = (180 - 10)\degree \\ \\ 5x = 170\degree \\ \\ x = \frac{170}{5} \\ \\ \bold{x = 34\degree}$

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$(2x - 10)\degree = 2 \times 34 - 10 \\ \\ (2x - 10)\degree = 68 - 10 \\ \\ \bold{(2x - 10)\degree = 58\degree}$

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$(3x + 20)\degree = 3 \times 34 + 20 \\ \\ (3x + 20)\degree = 102 + 20 \\ \\ \bold{(3x + 20)\degree = 122\degree}$

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in 2nd figure ,

$seg \: ab \: \parallel \: seg \: ce \: \\ \\ ac \: is \: a \: transversal \: \\ \\ \angle \: bac \: = \: \angle \: ace \: \\ \\ \bold{60\degree \: = \: \angle \: ace \: }$

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$\angle \: bca \: + \angle \: ace \: + \angle \: ecd = 180\degree \\ \\ \angle \: bca \: + 60\degree \: + 65\degree \: = 180\degree \\ \\ \angle \: bca \: = 180\degree - ( \: 60\degree \: + \: 65\degree \: )$

$\angle \: bca \: = \: 180\degree \: - 125\degree \\ \\ \bold{\angle \: bca \: = \: 55\degree}$

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