Chemistry, asked by amigod, 1 year ago

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Answered by Nidhi864
1
log(2.47*10^-29)


= log2.47 + log10^-29


=0.392-29


=-28.60

Answered by Anonymous
1
=log 247/100×log 10^-29
log 247- log 100×log ^-29
log 247-2×log 1- log 10^29
2.39-2×0-29
2.39-29
-26.61

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