Math, asked by aathsha, 1 year ago

plse derive sin^3 =1/3 (3sinx-sin3x)

Answers

Answered by 8837
2
hey user
1st of all your question is wrong its:- sin^3X= 1/4(3sinx-sin3x)

We know that the formula is:-
sin3A=3sinA-4sin^3A

4sin^3A= 3sinA - sin3A
then
sin^3A = 3 sinA-sin3A/4

or sin^3A=1/4 sinA -sin3A

its proved

i think its help you ✌
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