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Make the stoichiometric interpretation of the following equation:
2Al2O3 + 3C → 4Al + 3CO2
How many grams of aluminum metal will be obtained from 204 grams of aluminum oxide according to the
equation?
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Answer:
(204 g)/(101.96 g/mol) = 2.001 mol. 2(2.001) = 4.002 moles of aluminium in the sample. Then there are (4.002 mol)(26.98 g/mol) = 107.97 g of Al. Since the given mass has only 3 significant figures, round this answer to 108 g.
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