Question

plseeeeee gave the answer with full explanation.....

If ur answer will super I will mark u as a BRAINLIEST

Answer 1

at a height R above the earth surface g will be

gn=g(1+h/R)^-2

gn=g(1+2R/R)^-2

gn=g(1+2)^-2

gn=g/9

T=2pi√(l/g)

T1=2pi(√l/g)

T2=2pi(√l/gn)

T2=2pi(√l/g/9)

T2=2pi(√l/g)*3

T2=T1*3

T2/T1=3

Answer 2

$<b>Hello Friend<b>$ ❤️❤️


The answer of u r question is...✌️✌️


✖️Please give me the answer with full explanation✖️


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$gn = g(1 + \frac{h}{r} {)}^{ - 2}$



$gn = g(1 + { \frac{2r}{r} })^{ - 2}$



$gn = g(1 + 2) {}^{ - 2}$




$gn = {g}^{9}$




$t = 2\pi \: \sqrt{( \frac{l}{g} })$


$t1 = 2\pi \sqrt{ (\frac{l}{g} })$




$t2 = 2\pi \sqrt{ \frac{l}{gn} }$




$t2 = 2\pi \sqrt({ \frac{l}{g} } ) {}^{3}$



$t2 = t1 {}^{3}$


$= \frac{t2}{t1} = 3$



Hope it helps uu buddy!❤️


Thank you...☺️☺️