Math, asked by prithvi4321, 5 days ago

plspls any one can solve this maths equation If you give correct answer I will give heart and brainlest and rating but if anyone gives wrong answer or spam I will report #nospam
pls give correct answer ​

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Answers

Answered by MystícPhoeníx
23

Answer:

  • Option (b) 79.2 cm² is the required area of ∆ ABC .

Step-by-step explanation:

According to the Question

It is given that,

  • Base of Triangle ,b = 22cm
  • Height of triangle ,h = 7.2 cm

we have to calculate the area of given triangle .

The area of triangle is calculated by

  • Area of Triangle = 1/2 × base × height

by putting the value we get

→ Area of ∆ABC = 1/2 × 22 × 7.2

→ Area of ∆ABC = 11 × 7.2

→ Area of ∆ABC = 79.2 cm²

  • Hence, the area of ABC is 79.2 cm².

Option (b) 79.2 cm² is the required answer .

Additional Information !!

\begin{gathered}\boxed{\begin {array}{cc}\\ \quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}

Answered by PratyushYadav15
6

Answer:

79.2cm square

Step-by-step explanation:

Area of triangle = 1/2base * height

Base = 22cm

Height = 7.2cm

22 * 7.2 = 158.4

158.4 divided by 2 is 79.2cm

So the answer in 79.2cms square

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