Question

plss ans and help..
I'm in an exam and need ans.. ​

Answer 1

Answer:

$a) \: 5 \: \frac{m}{ {s}^{2} }$

b) 140 m

$c) \: 20 \: \frac{m}{s}$

Step-by-step explanation:

a) Acceleration of the car = (V final - V initial) / Time

= (20 - 0) / 4

= 20/4 = 5 m/s^2

b) Distance of the car = area under the speed time graph

area of trapezium = 1/2 × ( Sum of parallel sides ) × height

= 1/2 × ( 4 + 10 ) × 20

= 14 × 10 = 140 m

c) maximum velocity of the car is 20 m/s