Question

Plss ans correctly and if h dont know plss dont ans also .... and if possible send me the ans on a page written

Answer 1

Answer of 1st Question.

I am assuming the triangle to be a right angled triangle..

Let the longest length of the triangle be c

Using Pythagoras theorem,

$\sf 6^2 + 8^2 = c^2$

$\sf \implies 36+64=c^2$

$\sf \implies 100=c^2$

$\sf \implies \sqrt{100}=c$

$\sf \implies 10=c$

Therefore the length of the third side is 10cm.

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Answer of 2nd Question.

Given:- AO = 35m

• OB = 12m

To find

AB

Solution

Since, it's forming a right angled triangle, therefore we can conclude,

$\sf AO^2 + OB^2 = AB^2$

$\sf \implies (35)^2 + (12)^2 = AB^2$

$\sf \implies 1225 + 144 = AB^2$

$\sf \implies 1369 = AB^2$

$\sf \implies \sqrt{1369}= AB$

$\sf \implies 37 = AB$

Therefore, he is 37m far from the starting point.

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Answer for third question.

★Given:-

• Length = 24cm
• Breadth = 7cm

★To find:-

Length of the diagonal

★Solution:-

Formula to find length of diagonal when length and breadth is given,

$\qquad\qquad\qquad\bigstar\boxed{\bf d= \sqrt{ l^2 + b^2} }\bigstar$

Here, d is diagonal, l is Length and b is Breadth.

Using this formula

$\implies \sf d = \sqrt{(24)^2 + (7)^2}$

$\implies \sf d = \sqrt{576 + 49}$

$\implies \sf d = \sqrt{625}$

$\implies \sf d = 25$

Therefore, the length of the diagonal is 25cm.

$\mathcal{HOPE \ IT \ HELPS}$