Math, asked by gourisuresh, 1 year ago

Plss ans the attached que

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Answered by kaushik05
7

Answer:

 \frac{1}{2}  log( {e}^{2x}  +  {e}^{ - 2x} )  + c

where c is integral constant

Step-by-step explanation:

In this type of questions ,we have to use Integration by method of substitution .

Let t =e^2x+e^-2x

then dt =2(e^2x-e^-2x)dx

=dt/2=(e^2x-e^-2x)dx

now put the value in the question

soln refers to the attachment ...

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Answered by rishu6845
5

Answer:

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