Question

Plss answer fast!! tan(45-A)tan(45+A)=?

Answer 1

Answer:

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Step-by-step explanation:

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$\tan( \alpha ) = \cot(90 - \alpha )$

So tan(45-A) can be written as

cot(90-45+A)=Cot(45+A)

So we get

Cot(45+A)×Tan(45+A)

Now as

$\cot( \alpha ) = \frac{1}{ \tan( \alpha ) }$

Again write Cot(45+A)

As. 1/tan(45+A)

We get

$\tan(45 + a) \times \frac{1}{ \tan(45 + a) }$

So answer is 1

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Answer 2

1 is the answer

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