Question

plss answer following question

Answer 1

Answer:

Option (a) is correct

Step-by-step explanation:

Edge of the cube (a) = 22 cm

Diameter of the sphere (d)=0.5 cm

$Radius (r)=\frac{d}{2}\\=\frac{0.5}{2}=\frac{1}{4}\:cm$

$Volume \:of \:empty\:space \\=\frac{1}{8} \:of \: volume \:of\:cub\\=\frac{a^{3}}{8}$

$Volume \:of \: occupied\:space(V_{1}) = a^{3}-\frac{a^{3}}{8}\\=\frac{8a^{3}-a^{3}}{8}\\=\frac{7a^{3}}{8}$

$Let\:the\: number \:of \\marbles \:accommodated =n$

$n = \frac{V_{1}}{Volume\:of \:each \: sphere}$

$=\frac{\frac{7a^{3}}{8}}{\frac{4}{3}\times \pi r^{3}}$

$=\frac{\frac{7}{8}\times (22)^{3}}{\frac{4}{3}\times \frac{22}{7}\times \frac{1}{4^{3}}}$

$=142296$

Therefore,.

Option (a) is correct.

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