Question

plss answer it.........​

Answer 1

Answer:

In ΔOAF and ΔOBD,

<O = <O (Same angle)

Therefore, ΔOAF ~ ΔOBD (AA similarity)

So, OA/OB = FA/DB ------(1)

Similarly, In ΔFAC and ΔEBC,

So, FA/EB = AC/BC------(2)

But EB = DB,

So, FA/DB = AC/BC

By (1) and (2)

OA/OB = AC/BC

==> OA/OB = (OC - OA)/(OB - OC)

==> (OA + OB) * OC = 2 OA * OB

==> (1/OA) + (1/OB) = (2/OC)