Question

plss answer me correctly plss this is exam plss friends plss​

Answer 1

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Answer 2

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$For \: the \: zero \: of \: polynomial \\ </p><p></p><p>\sf{}P(x) = {x}^{2} - 5x + 6 \\ \\ \\ \\ \\ \\ \\ P(x)=x </p><p>2</p><p> −5x+6</p><p></p><p> \\ We \: have \: </p><p></p><p>\sf{}P(x) = 0P(x)=0</p><p></p><p>\implies \sf{} {x}^{2} - 5x + 6 = 0 \\ ⟹x </p><p>2</p><p> −5x+6=0</p><p></p><p> \\ \: \\ \implies \sf{} {x}^{2} - (3 + 2)x + 6 = 0 \\ ⟹x </p><p>2</p><p> −(3+2)x+6=0</p><p></p><p> \\ \implies \sf{} {x}^{2} - 3x - 2x+ 6 = 0 \\ ⟹x </p><p>2</p><p> −3x−2x+6=0</p><p></p><p> \\ \implies \sf{}x(x - 3) - 2(x - 3)= 0⟹x(x−3)−2(x−3)=0</p><p></p><p> \\ \implies \sf{}(x - 3) (x - 2)= 0⟹(x−3)(x−2)=0</p><p></p><p> \\ \\ \\ If \: product \: of \: two \: real \: numbers \: are \: zero \: then \: either \: one \: of \: them \: are \: zero</p><p></p><p> \\ \sf{}either \: \: (x - 3) = 0 \: \: \\ or \\ \: \: (x - 2)= 0 \\ either(x−3)=0 \\ or \\ (x−2)=0</p><p></p><p>\sf{}(x - 3) = 0 \\ \: \: \\ gives \: \: x = 3(x−3)=0givesx=3</p><p></p><p>\sf{}(x - 2) = 0 \: \: gives \: \: x = 2(x−2)=0 \\ \: givesx=2$