Math, asked by arihantjain4663, 1 month ago

plss answer the given attachment

Attachments:

Answers

Answered by XxMrZombiexX
73

Question ;

  • In Fig. AB || CD  ∠APQ = 50° and  ∠PRD = 127° .Find x and y

 \quad \rule{80mm}{0.5mm}

 \:  \:  \:  \:  \:  \: \large{\underbrace{\underline{ \pmb{Answer }}}}

  • x = 50°
  • y = 77°

Step-by-step explanation

Given data

  • AB ||CD
  • ∠APQ = 50° and
  • ∠PRD = 127°

We need to Find out

  • Angle x and Angle Y ?

Solution

AB||CD PQ straight line intersects these at P and Q. 

Therefore ,

  \\ :  \longmapsto \qquad \qquad \:  \text{∠APQ = ∠PQR}  \:  \qquad  \bigg \{ \text{alternate angles} \bigg \} \\  \\  \\

 \\   :  \longmapsto \qquad \qquad \:   \angle50 \degree \:  =  \angle \: \text{ PQ R} \\  \\

 \\  \large \pink {:  \longmapsto \qquad \qquad \:  \boxed{ \frak x \:  = 50 \degree}} \\  \\

Similarly, AB||CD PR straight line intersects these at P and R.

Therefore ,

  \\ :  \longmapsto \qquad \qquad \:  \text{∠APR= ∠PRD}  \:  \qquad  \bigg \{ \text{alternate angles} \bigg \} \\  \\

 \\  :  \longmapsto \qquad \qquad \sf \angle APQ +  \angle \: QPR = \angle \: PRD  \:  \\ \\

 \\  :  \longmapsto \qquad \qquad \sf 50 \degree +  \angle \: QPR = 127 \degree  \:  \\ \\

 \\    \sf:  \longmapsto \qquad \qquad \angle  \: QPR = 127 \degree - 50 \degree \\  \\

 \\  \large  \pink{  \sf:  \longmapsto \qquad \qquad  \boxed{\boxed{  \pmb{\angle  \:QPR =  77 \degree}}} }\\  \\

 \bigstar  \fbox{\boxed{ \text{Hence The Value Of \green{ x=50° }And  \green{y =77°}}}} \bigstar

 \quad \rule{80mm}{0.5mm}

Similar questions