Question

plss answer this..I go mark as brainliest only those who give crct answers​

Answer 1

Step-by-step explanation:

Answer is 2cm....

Regards

Answer 2

Answer:

answer is 2

Step-by-step explanation:

Let 0P=OQ= r ( radii of same circle)

Now,

PB=BQ

AP=AR. (tangent segment theorem) [1]

CQ=CR

But angle(B =90°)

and angle (P=Q=90°). {tangent theorem}

Therefore. quadrilateral PBQO is a rectangle

Therefore,PB=OQ=r

BQ =OP=r

Now AP= AB-PB =8-r

and QC =BC-BQ=6-r

But

AC=AR+RC

10 =AP+CQ. PYTHAGOREAN TRIPLET for

6,8,10) ................from [1]

10 = 8-r + 6- r

10 = 14-2r

14-10=2r

4 = 2r

r= 4÷2

r = 2