Math, asked by sumaiya3927, 3 months ago

plss answer this question​

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Answered by Ganesh094
6

\sf Answer

 \sf c) f_{3}(x)

\sf Given

  \sf \: f_{1}(x) =  \frac{1}{x} \\  \sf f_{2}(x) = 1 - x  \\ \sf f_{3}(x) =  \frac{1}{1 - x} \\  \sf(f_{2} \times J \times f_{1})(x) = f_{3}(x) \\ \sf  f_{2}( J \times f_{1})(x) ))= f_{3}(x)  \\ \sf  f_{2} \times J\binom{1}{x}  =  \frac{1}{1 - x} \\  \sf 1 -  J\binom{1}{x}   =  \frac{1}{1 - x}   \\ \sf  J\binom{1}{x}  = 1 -  \frac{1}{1 - x} =    \sf\frac{ - x}{1 - x}  =  \frac{x}{x - 1}    \\ \sf now  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x  ➝ \frac{1}{x} \\   \sf J(x) =  \frac{1 \div x }{1 \div x - 1 =  \frac{1}{1 - x} }  =  f_{3}(x)

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