Question

plss Answer this question.

Answer 1

Given R = 10%, T = 2 years.

We know that SI = PRT/100

                           = P * 10 * 2/100

                           = 20P/100

                          = P/5.

We know that CI = [P(1 + r/100)^n] - 1

                            = [P(1 + 10/100)^2] - 1

                            = [P(1 + 1/10)^2] - 1

                            = [P(11/10)^2] - 1

                            = P[121/100] - 1

                            = P[21/100]

                            = 21P/100.

Given that Difference between SI and CI on a sum is 65.

= > (21P/100) - (P/5) = 65

= > 21P - 20P = 6500

= > P = 6500.

Therefore, the sum is 6500.

Hope it helps!