plss answer this question its urgent
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hi frnd! your answer is as follows
(ii) first do parllel combenation ;
1/r=1/6 + 1/6 + 1/6
1/r= 1+1+1/6
1/r=3/6
1/r=1/2
r = 2 ohm
so its mean that in this the resistor are connected in parllel
(i) secondaly do in series
R=6+6+6
R=18
ATO
R/r =18/2=9
therefor answer is 9 ohm
(ii) first do parllel combenation ;
1/r=1/6 + 1/6 + 1/6
1/r= 1+1+1/6
1/r=3/6
1/r=1/2
r = 2 ohm
so its mean that in this the resistor are connected in parllel
(i) secondaly do in series
R=6+6+6
R=18
ATO
R/r =18/2=9
therefor answer is 9 ohm
thakurpintu84:
your second answer is wrong
Answered by
1
(i) connect two resistors in paralel and one in series
then resistance for the two resistors in parallel
1/6+1/6=i/R
R=3Ω
6Ω+3Ω=9Ω
(ii)connect all the resistors in parallel
then 1/R=1/6+1/6+1/6
R=2Ω
then resistance for the two resistors in parallel
1/6+1/6=i/R
R=3Ω
6Ω+3Ω=9Ω
(ii)connect all the resistors in parallel
then 1/R=1/6+1/6+1/6
R=2Ω
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